![Parameter Parameter](/uploads/1/2/5/5/125555631/397117227.png)
Originally posted by Mathias Schneider:Thats wrong!!In Java all parameters are passed by reference, even Strings and booleans!Ummm. EVERYTHING IN JAVA IS PASS BY VALUE. There are no exceptions. When you 'pass an object', what you are really doing is passing the value of the reference to the object.You do not have direct access to object in java. When you sayFoo myFoo = new Foo;myFoo is a reference to the object, not the object itself. Basically, it's the address of the object. So when you pass it in to a method:myMethod(myFoo);you pass a copy of the address.
![Parameter Java Adalah Parameter Java Adalah](/uploads/1/2/5/5/125555631/498593100.png)
There are different ways in which parameter data can be passed into and out of methods and functions. Let us assume that a function B is called from another. Pengertian Parameter. Parameter adalah tempat penyimpanan (variabel) di dalam function, yang digunakan untuk melakukan pemeberian data dari pemanggil ke dalam function.Parameter terletak di antara tanda kurung ( dan ) setelah identitas dari function, dan sebuah function dapat memiliki beberapa parameter yang dipisahkan dengan tanda koma.
Other languages use pass-by-reference or pass-by-pointer. But in Java no matter what type of argument you pass the corresponding parameter (primitive variable or object reference) will get a copy of that data, which is exactly how pass-by-value (i.e. Copy-by-value) works.In Java, if a calling method passes a reference of an object as an argument to the called method then the passed-in reference gets copied first and then passed to the called method. Both the original reference that was passed-in and the copied reference will be pointing to the same object. So no matter which reference you use, you will be always modifying the same original object, which is how the pass-by-reference works as well.